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Lots of operators are non-commutative. You can't "break" a commutative property that doesn't exist because the operator is not yet defined.
by ivanbakel 8y ago
Lots of operators are non-commutative. You can't "break" a commutative property that doesn't exist because the operator is not yet defined.
- reallydude 8y ago> You can't "break" a commutative property that doesn't exist because the operator is not yet defined. That's the point (eg modulus). There's an entire preamble that's not relevant to the decision. The coverage of the inane "insights" is some hero worship hype.