3 ms·
For comparison infix notation with the same precedence for all operators: (x * (y + z)) eql ((x * z) + (y * z)) Or: (y + z * x) eql (x * z + (y * z))
by zzzcpan 8y ago
For comparison infix notation with the same precedence for all operators:
(x * (y + z)) eql ((x * z) + (y * z))
Or:
(y + z * x) eql (x * z + (y * z))
With different precedence:
x * (y + z) eql x * z + y * z
But now you have to remember precedences and mentally regroup the expression.