4 ms·

I don't know any Lisp, but I would decode (= (* x (+ y z)) (+ (* x z) (* y z))) As x(y + z) = xz + y*z e.g. (+ y z) means you add y and z wit

I don't know any Lisp, but I would decode (= (* x (+ y z)) (+ (* x z) (* y z))) As x*(y + z) = x*z + y*z e.g. (+ y z) means you add y and z with highest priority.

grenoire 8y ago
Which is incorrect, they aren't equal.
- nanaya 8y ago
  Well, technically it solves to x = z when y <> 0 and any x, z when y = 0 though I'm not sure if that's the original intention.
- Retra 8y ago
  That is probably not a statement of equality, but a boolean test for it.