3 ms·
The Big Theta of N^N^N^N is O(n * sqrt(n)) :)
by arthev 8y ago
The Big Theta of N^N^N^N is O(n * sqrt(n)) :)
- logv 8y agowow, that's way off! for n = 2, n^n^n^n returns 65536. for n = 3, javascript thinks its infinity. i guess BOAT should start using decimal values for n so we can detect this problem.