3 ms·
Not much of an improvement, but never worse -- unless the function is not injective. You can't argue with Kolmogorov complexity. If the algorithm is secret and
by pishpash 8y ago
Not much of an improvement, but never worse -- unless the function is not injective. You can't argue with Kolmogorov complexity. If the algorithm is secret and has computational complexity it gets better.
- usrusr 8y agoSure, but we are talking about trivial substitution schemes here. I could have been more specific.