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I don’t think C++’s “Pay for what you use” applies here. You don’t have to use something just because it’s in the standard library. The only practical differenc
by stochastic_monk 8y ago
I don’t think C++’s “Pay for what you use” applies here. You don’t have to use something just because it’s in the standard library.
The only practical difference for a user is a larger binary when statically linking.
(The burden on compiler developers is a very real concern, however.)