Just a small fix for those that were checking as I was If the ground distance each way is D, airspeed is V, and wind speed relative to the ground is w, total t

Just a small fix for those that were checking as I was If the ground distance each way is D, airspeed is V, and wind speed relative to the ground is w, total time is D/(V-w) + D/(V+w) = 2DV/(V^2-w^2) = 2D/((V^2-w^2)/V). For 0 < w < V: this is more than the 0 wind case. For w >= V: the headwind is so high that you can't make any progress toward the destination). The last result being somehow obvious ;)