3 ms·
<pedant mode>Technically it would be airplane speed + wind speed vector for the same direction the airplane is heading.</pedant mode> :)
by cyberferret 8y ago
<pedant mode>Technically it would be airplane speed + wind speed vector for the same direction the airplane is heading.</pedant mode> :)
- TheCraiggers 8y agoHey, I said 'basically'! :P But yes, you are correct. However, the person I was replying to already said they were ignorant of this stuff, so I didn't want to get too crazy.