3 ms·
A change in structure might be helpful: $ ls data 0001.csv 0002.csv 0003.csv 0004.csv ... $ ls algorithm_a 0001.csv 0002.csv 0004.csv ... $
by boomlinde 8y ago
A change in structure might be helpful:
$ ls data
0001.csv 0002.csv 0003.csv 0004.csv ...
$ ls algorithm_a
0001.csv 0002.csv 0004.csv ...
$ diff -q algorithm_a data |grep ^Only |sed 's/.*: //g'
0003.csv ...
- v3gas 8y agoExcellent point, haha!