5 ms·
You talked about having "a member" and getting to every other member with scalar multiplication only. But even given a 2-member basis for R2, how are you plann
by zazen 8y ago
You talked about having "a member" and getting to every other member with scalar multiplication only. But even given a 2-member basis for R2, how are you planning on using 2 members, with scalar multiplication only?
I'm afraid you have badly misremembered this stuff.
- dxbydt 8y agoyou are right.