4 ms·
In some deep sense, what you are saying is true : for example, if an infinite sequence of numbers is sufficiently dense, then it has arbitrarily long arithmetic
by sn41 8y ago
In some deep sense, what you are saying is true : for example, if an infinite sequence of numbers is sufficiently dense, then it has arbitrarily long arithmetic progressions.[1] On the other hand, Rankin in 1990 constructed a set with positive density which does not have long geometric progressions.
[1] https://en.wikipedia.org/wiki/Szemer%C3%A9di%27s_theorem https://en.wikipedia.org/wiki/Szemer%C3%A9di%27s_theorem