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This is awesome. How did you figure this out? The documentation on `split` says: "The pattern can be a &str, char, or a closure that determines the split." Bu

This is awesome. How did you figure this out? The documentation on `split` says: "The pattern can be a &str, char, or a closure that determines the split." But in your case it is an array of chars and it splits for each of them. I don't see this documented at all.

gridspy 8y ago
Vec<char> or an array for instance - [char; 20] can (automatically) create a "slice" of type &[char]. This is true for all types (not just char). The operator for this is for eg l[1..10]. It can also happen automatically. &str is the same type as &[char] - just a renaming. Still learning Rust myself, apologies if this leads you astray. Just do some reading on slices. https://doc.rust-lang.org/book/ch04-03-slices.html#string-slices https://doc.rust-lang.org/book/ch04-03-slices.html#string-sl... https://doc.rust-lang.org/std/slice/ https://doc.rust-lang.org/std/slice/
- steveklabnik 8y ago
  &str is not the same as &[char]. &str has the same memory representation as &[u8]. char is four bytes, not one.
  - gridspy 8y ago
    Thanks Steve.
    - steveklabnik 8y ago
      No problem! It's an easy mistake to make.
steveklabnik 8y ago
Would you be willing to file a docs bug so we can clarify this? It’s possible that it used to be only those types, but was expanded. We should fix this!
- terhechte 8y ago
  Yeah, will do
  - steveklabnik 8y ago
    Awesome, thank you!
general_pizza 8y ago
The docs are a tad misleading but the important piece is to look at the signature. The `where P: Pattern<'a>` portion states that split needs a type that implements the Pattern trait. If you follow the link to the Pattern trait then at the bottom you'll see a section[0] listing types implementing the trait (&[char] being one) and therefore can be passed into split. Hope that helps! [0] https://doc.rust-lang.org/std/str/pattern/trait.Pattern.html#implementors https://doc.rust-lang.org/std/str/pattern/trait.Pattern.html...

gridspy 8y ago

Vec<char> or an array for instance - [char; 20] can (automatically) create a "slice" of type &[char]. This is true for all types (not just char). The operator for this is for eg l[1..10]. It can also happen automatically. &str is the same type as &[char] - just a renaming. Still learning Rust myself, apologies if this leads you astray. Just do some reading on slices. https://doc.rust-lang.org/book/ch04-03-slices.html#string-slices https://doc.rust-lang.org/book/ch04-03-slices.html#string-sl... https://doc.rust-lang.org/std/slice/ https://doc.rust-lang.org/std/slice/

steveklabnik 8y ago
&str is not the same as &[char]. &str has the same memory representation as &[u8]. char is four bytes, not one.
- gridspy 8y ago
  Thanks Steve.
  - steveklabnik 8y ago
    No problem! It's an easy mistake to make.

steveklabnik 8y ago

Would you be willing to file a docs bug so we can clarify this? It’s possible that it used to be only those types, but was expanded. We should fix this!

terhechte 8y ago
Yeah, will do
- steveklabnik 8y ago
  Awesome, thank you!

general_pizza 8y ago

The docs are a tad misleading but the important piece is to look at the signature. The `where P: Pattern<'a>` portion states that split needs a type that implements the Pattern trait. If you follow the link to the Pattern trait then at the bottom you'll see a section[0] listing types implementing the trait (&[char] being one) and therefore can be passed into split. Hope that helps! [0] https://doc.rust-lang.org/std/str/pattern/trait.Pattern.html#implementors https://doc.rust-lang.org/std/str/pattern/trait.Pattern.html...