3 ms·
Vanilla JavaScript: function getSpells(person) { if(person.type != "Wizard") throw new Error("person.type=" + person.type + " is not Wizard");
by z3t4 8y ago
Vanilla JavaScript:
function getSpells(person) {
if(person.type != "Wizard") throw new Error("person.type=" + person.type + " is not Wizard");
}