3 ms·
g f x would not be the same as (g . f) x you need the right associative function application operator $, ie. g $ f x or simply g (f x)
by solinent 8y ago
g f x
would not be the same as
(g . f) x
you need the right associative function application operator $, ie.
g $ f x
or simply
g (f x)
- platz 8y agoi know that, i was just highlighting the appearance of the order of the letters without considering associativity.