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I think you could actually approximate an unobstructed hyperbolic plane to arbitrary precision with portals. In this game, the hyperbolic plane is represented a
by wcoenen 8y ago
I think you could actually approximate an unobstructed hyperbolic plane to arbitrary precision with portals. In this game, the hyperbolic plane is represented as a tiling of hexagons and heptagons: https://www.youtube.com/watch?v=lX5eCfRSCKY&t=742s https://www.youtube.com/watch?v=lX5eCfRSCKY&t=742s
If you take this model but upgrade each cell to a little 3D euclidean region, then you could completely surround it by portals that connect it to the neighbouring cells. The edges of the portals wouldn't be visible. The smaller the euclidean cells, the better the approximation to the hyperbolic plane.
- zenorogue 8y agoFor easy computations assume octagonal cells. Their vertices will have 135 degrees each. The edges of the portal will be visible because the left and right images do not match (since 3*135 ≠ 360). And a object (as long as it is modelled as an Euclidean 3D object, not a point) will not be able to go through such a vertex.