See also rsplit(':', 1). But instead of either of those, you should really be using library functions that already understand the format in question instead of

See also rsplit(':', 1). But instead of either of those, you should really be using library functions that already understand the format in question instead of making up your own rules. >>> u = urllib.parse.ParseResult('', '[2001:0db8:f00f::0553:1211:0088]:10443', '', '', '', '') >>> u.hostname '2001:0db8:f00f::0553:1211:0088' >>> ipaddress.ip_address(u.hostname) IPv6Address('2001:db8:f00f::553:1211:88') >>> u.port 10443