Not really, after $p = $z++ $p is 'z', $z is 'aa', as you'd kind-of expect. But the difference between literals and expressions/variable references of course ju

Not really, after $p = $z++ $p is 'z', $z is 'aa', as you'd kind-of expect. But the difference between literals and expressions/variable references of course just adds icing to the cake of bizareness.