3 ms·
Or to be even mooooooore pedantic the fsharp functions would probably be written to be seq<'a> -> seq<'a>, so that would be Func<IEnumerable<T>, IEnumerable<T>>
by AdeptusAquinas 8y ago
Or to be even mooooooore pedantic the fsharp functions would probably be written to be seq<'a> -> seq<'a>, so that would be Func<IEnumerable<T>, IEnumerable<T>> where T : IComparable<T> :)