Just think about the amount of data stored on a DVD. It's about 4 GB, which means that if you got a perfect image of just the data of the DVD (one pixel imagin

Just think about the amount of data stored on a DVD. It's about 4 GB, which means that if you got a perfect image of just the data of the DVD (one pixel imaging each bit) the size of the picture would also be 4 GB. That means, as far as I understand, a 4 gigapixel image AT BEST, assuming you were able to get every single pixel to capture one bit of data on the DVD. In reality, since DVDs are circular and images are square you're looking at images that would be more like 6 gigapixel if my math is correct. Today, available cameras are at best 50-megapixels, which means you need at the very minimum about 100 photos of each DVD, but in reality, there is no way you can ever get one bit per pixel, because to begin with the bits are not aligned in rows unlike the camera's pixels, so you're most probably looking at ten times that. It's an interesting idea but I'm pretty sure it's completely unpractical. Edit and I realised I counted 4 GB, but I should actually have used 32 Gb as a starting number, as what matters here are the bits, not the bytes, so add another 8x to the amount of photos you need.