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FWIW, with a little syntactic trick, you can actually have sigillless variables in Perl 6: my \foo = $ = 42; # bind sigilless name to a container with 42
by lizmat 8y ago
FWIW, with a little syntactic trick, you can actually have sigillless variables in Perl 6:
my \foo = $ = 42; # bind sigilless name to a container with 42
say foo; # 42
foo = 666;
say foo; # 666
See https://opensource.com/article/18/9/using-sigils-perl-6 https://opensource.com/article/18/9/using-sigils-perl-6 for more information. </plug>