3 ms·
Pretty much, although O() notation doesn't really work with constants.
by JoachimSchipper 16y ago
Pretty much, although O() notation doesn't really work with constants.
- StavrosK 16y agoI know, but it was the most concise way I could express it.
- BrandonM 16y agoIs there a problem with just leaving off the O() altogether?
- silentbicycle 16y agoRight. Big O notation usually excludes constant factors, but here, the constant factors are the point.