3 ms·
Saying “equal to any 0-valued pointer” there can be misleading. It is true of a pointer assigned from a (foo*)0 constant, but not true of a pointer to a hardwar
by kps 8y ago
Saying “equal to any 0-valued pointer” there can be misleading. It is true of a pointer assigned from a (foo*)0 constant, but not true of a pointer to a hardware address 0 or a pointer with bits all 0 (assuming they exist).