3 ms·
Thought experiment: Suppose you bet 100% of your bankroll every round. If at any point you lose a round, your bankroll is now $0. Any money you made from former
by Double_Cast 8y ago
Thought experiment: Suppose you bet 100% of your bankroll every round. If at any point you lose a round, your bankroll is now $0. Any money you made from former rounds is for naught. Whoops.
bankroll_final = (bankroll_initial)(round_1)(round_2)(round_3)(...)(round_n)
$0 = (bankroll_initial)(210% )(210% )(210% )(...)(0% )
Taking the "non-log" Expected Value would be optimal if your bankroll were "renewed" to the same constant each round. Because the outcome of each individual round would be independent from other rounds.
Bankroll_final = (bankroll)(round_1) + (bankroll)(round_2) + (...) + (bankroll)(round_n)
But since the outcome of each round depends on previous rounds, we want to optimize for Expected Value of Growth. For which we'll use a geometric mean rather than an arithmetic mean. Also,
EV[bankroll_final] = EV[(bankroll_initial)(round_1)(round_2)(round_3)(...)(round_n)]
is equivalent to
EV[bankroll_final] = EV[(bankroll_initial) e^ln(r1 + r2 + r3 + (...) + r_n)]
which allows us to discuss wagers in terms of e^(x) and in terms of growthrates.