3 ms·
By "first inaccessible ordinal" you mean epsilon_0? (Probably you mean it in the sense of the first one inaccessible by addition, multiplication and exponentiat
by ASipos 8y ago
By "first inaccessible ordinal" you mean epsilon_0? (Probably you mean it in the sense of the first one inaccessible by addition, multiplication and exponentiation.) Because there is also a "first recursively inaccessible ordinal", which is much larger (also, not recursive: it's used to construct, by collapsing, the ordinal of Delta12-CA+BI, which is also much larger though recursive).
- jesuslop 8y agoYes I was being sloppy. epsilon_0 as the limit of iterating ordinal exponentiation by omega. Also the correct volumen is number 3.