4 ms·

No, I believe the formula for multisets would be M(x) = ∑n (A(A+1)(A+2)..(A+n-1))/n! since there are (n+k+1)c(k+1) possible unordered n-tuples over a se

by wz1000 8y ago

No, I believe the formula for multisets would be M(x) = ∑n (A*(A+1)*(A+2)..(A+n-1))/n! since there are (n+k+1)c(k+1) possible unordered n-tuples over a set with cardinality k.