3 ms·
How do you interpret the derivative of that? It's now log(2)*2^A. What does "log(2)" mean as a type here? Do you expand it back out as a taylor series like in
by zawerf 8y ago
How do you interpret the derivative of that? It's now log(2)*2^A.
What does "log(2)" mean as a type here? Do you expand it back out as a taylor series like in the circular list example?