3 ms·
I have explicitly mentioned this: > [...] some have converged to base 85 (because 85^5 / 2^32 ~= 1.03, i.e. just enough to represent 4 octets in 5 units). Bas
by lifthrasiir 8y ago
I have explicitly mentioned this:
> [...] some have converged to base 85 (because 85^5 / 2^32 ~= 1.03, i.e. just enough to represent 4 octets in 5 units).
Base 85 does not use bigint, it is just a clever approximation of optimal encoding with 85 symbols.
- eesmith 8y agoI think I was confused between "baseX" as the specific program name and 'base X' as the base of the specific numbering system.