2 ms·
I guess you could make pipe variadic: function pipe(val, ...funcs) { for (let f of funcs) val = f(val); } EDIT: seems like I got ninja'd by an e
by Leszek 8y ago
I guess you could make pipe variadic:
function pipe(val, ...funcs) {
for (let f of funcs) val = f(val);
}
EDIT: seems like I got ninja'd by an edit :)