Actually, since it's a ratio, the uniform distrubution is in the logarithmic domain, ie over [−log(3),+log(3)], so the probablity (assuming, for no good reason,

Actually, since it's a ratio, the uniform distrubution is in the logarithmic domain, ie over [−log(3),+log(3)], so the probablity (assuming, for no good reason, that it is a uniform distribution), would be: log 3 − log 2 1 − ───────────── ≈ 0.81546 log 3 − log ⅓ or just over four fifths. But as others have pointed out, the real answer is the question is broken, since we need a distribution for x, not a interval for x.