3 ms·
Is L1 the most efficient for a fixed size? The difference is ~6000 km for LEO versus 1.5 million km for L1 to the Earth's center and the r^2 law means you need
by tgb 8y ago
Is L1 the most efficient for a fixed size? The difference is ~6000 km for LEO versus 1.5 million km for L1 to the Earth's center and the r^2 law means you need to put a lot more area in L1 than in LEO, even after discounting for the fact that in LEO it'll be on the wrong side of the Earth half the time. Filling up appreciable fractions of LEO might have it's own problems.
- Retric 8y agor^2 is not that relevant. The moon is 384,400 km from the earth and can cause a total solar eclipse despite only being 3,474 km wide where the earth is 12,742 km wide. The geometry works out more or less linearly with distance. So 1.5 / 0.384 = 1.065. Which means and object 1.065x as wide as the earth would also provide a total solar eclipse. Making sunshades more than 2x effective L1 vs LEO. PS: Only 1/2 the time they are on the sun facing side, but they are not perpendicular with sunlight for that entire half. At a 45 degree angle a sunshade blocks ~70% as much sunlight vs a 0 degree angle.