No, it’s not, and even if it were true it wouldn’t disqualify lisp, since you can quite happily wield lisp in a context which lets you express logic in simpler/

No, it’s not, and even if it were true it wouldn’t disqualify lisp, since you can quite happily wield lisp in a context which lets you express logic in simpler/constrained forms. Consider hiccup, datalog DSLs, etc.