3 ms·
No it doesn't. In the 2/3 case, you're given information about the whole set, not just one member. Instead of "seeing one boy" affecting the gender of the other
by hexane360 8y ago
No it doesn't. In the 2/3 case, you're given information about the whole set, not just one member. Instead of "seeing one boy" affecting the gender of the other child, it's "seeing there are more than 0 boys" affecting the gender of one of the children.
Here's another example: If I flipped 100 coins, and told you there were 99 heads, what's the likelihood the other 1 was tails? The answer is 100/101, because there are 100 ways the one tail could happen, while only one way zero tails can happen. But if you're only told that the first 99 are heads, the answer is 1/2. You know the last flip has exactly the same odds as all the other ones -- the trials are independent. The difference is in one all the flips were included in the results (and the question isn't about any one specific flip), while in the other you had no information about the last flip (which the question was about).
Another way of looking at it: In the first example, the question was asking about the sum of 100 trials and you were given information about 99 of those 100 trials. You were given 99/100s of the information you need to answer the question. In the second example, the question was asking about the last trial and you were given information about 99 unrelated trials beforehand. You were given none of the information you need to answer the question.