4 ms·
It's not a paradox if you put it in less confusing language. There are 4 possibilities: GG GB BG BB GG is impossible so you have GB, BG, & BB. One of them is
by dumbfoundded 8y ago
It's not a paradox if you put it in less confusing language.
There are 4 possibilities:
GG
GB
BG
BB
GG is impossible so you have GB, BG, & BB. One of them is a B, what's the other. Well that's clearly 2 / 3 G.
The other one situation is completely. It's basically just the chance of a child being a girl.
- perl4ever 8y agoBut are those ordered pairs or sets of two items each?
- uryga 8y agoI think of them as ordered pairs, but would it change anything if they were sets? Order doesn't matter in this question.
- dumbfoundded 8y agoOrder doesn't matter but it helps make it more clear as why I included the same combination twice.
- Sean1708 8y agoIs this basically to do with the fact that you know how likely it is to see a boy given any of the combinations? So there's a 33% chance that there are two boys and you see a boy, a 33% chance that there's a boy and girl and you see a boy, and a 33% chance that there's a boy and a girl and you see a girl. Given that you've seen the boy you've eliminated one of the outcomes so the other two outcomes are equally likely?
- dumbfoundded 8y agoI'm confused by your comment but I'll try to explain more. Given one of the children is a boy. The only combinations possible are: GB, BG, & BB. Where G is Girl and B is Boy. The question is about the probability of the other child being a Girl. When we eliminate one of the B from each combination, we get: GB, BG, BB -> G, G, B We can see that 2/3 are G and 1/3 are B. Does this help?