2 ms·

They're the same, surely? (p/q)(p/q) = p(1/q)p(1/q) = pp(1/q)(1/q) = (pp)/(qq) Or (p/q)(p/q) = ((p/q)p)/q = ((pp)/q)/q = (p*p)/(

They're the same, surely? (p/q)*(p/q) = p*(1/q)*p*(1/q) = p*p*(1/q)*(1/q) = (p*p)/(q*q) Or (p/q)*(p/q) = ((p/q)*p)/q = ((p*p)/q)/q = (p*p)/(q*q)