2 ms·
Those statements are equivalent. If p and q share no common factors, then p^2 and q^2 also don't, so p^2/q^2 is still irreducible.
by tomsmeding 8y ago
Those statements are equivalent. If p and q share no common factors, then p^2 and q^2 also don't, so p^2/q^2 is still irreducible.