4 ms·
> Haskell being the exception due to the absence of quick and dirty mutability Haskell has ST for mutable local variables, and for the truly "quick and dirty"
by nybble41 8y ago
> Haskell being the exception due to the absence of quick and dirty mutability
Haskell has ST for mutable local variables, and for the truly "quick and dirty" cases there's always unsafePerformIO. What is it you're trying to express that wouldn't be handled by either of these options?