5 ms·
No, it's not. It's actually e ^ x_i / sum(e ^ x_j for x_j in x), which is in fact different. Simply dividing by the sum wouldn't work for "squashing to a probab
by Tenobrus 8y ago
No, it's not. It's actually e ^ x_i / sum(e ^ x_j for x_j in x), which is in fact different. Simply dividing by the sum wouldn't work for "squashing to a probability distribution" in a large number of cases.
- throwaway080383 8y agoSo pointwise exponentiation composed with dividing by the sum. Still don't need a new word.