3 ms·
True-ish. Since the formula uses confidence intervals[0] it does better with recent talks than a simple (likes - dislikes). But you're right, breaking into "a
by yaj54 8y ago
True-ish. Since the formula uses confidence intervals[0] it does better with recent talks than a simple (likes - dislikes). But you're right, breaking into "all time" status is tough because there are a number of talks with many hundreds of likes and 1 or 2 dislikes.
0: https://www.evanmiller.org/how-not-to-sort-by-average-rating.html https://www.evanmiller.org/how-not-to-sort-by-average-rating...