3 ms·
You can't do that with things that interact, e.g.: f(a,b) = b/a
by andrewprock 8y ago
You can't do that with things that interact, e.g.:
f(a,b) = b/a
- whatshisface 8y agof(a,b) = b/a = 0 + 0 + b/a = f(a) + f(b) + interaction term In this case the system is contained entirely within the interaction term, and since you don't know the distributions of a and b there's not much motivation to go further. If you had the distributions of a and b you might be able to do something a little less trivial by skewing the interaction term to have an expected value of zero, potentially like: a/b = a + b + (a/b - a - b) = f(a) + f(b) + (interaction term with E[term] = 0)
- andrewprock 8y agoIf by "interaction term" it is meant f(a,b), then I congratulate the author of that tautology.
- whatshisface 8y agoHidden in the parent's comment is the additional condition that f(a,b) have an expected value of zero. It's still pretty easy to prove, though.
- deleted 8y ago[deleted]