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" |u> can evolve independently of |v> " This is not unitary. Quantum theory has two parts: unitary evolution, and measurement processes. That's it.
by mathgenius 8y ago
" |u> can evolve independently of |v> "
This is not unitary. Quantum theory has two parts: unitary evolution, and measurement processes. That's it.
- monktastic1 8y agoEh? If U is a unitary operator that can act on |u>, then U @ I is a unitary operator on the state |u> @ |v>, producing U|u> @ |v>. Can you explain what you mean?