4 ms·
Doesn’t that assume |v> evolves the same way |u> does (according to U)?
by antidesitter 8y ago
Doesn’t that assume |v> evolves the same way |u> does (according to U)?
- mathgenius 8y agoAnything else is not unitary evolution.
- antidesitter 8y agoWhat do you mean? Let u and v be qubits. Apply a Hadamard gate to u while leaving v unchanged. Then they have evolved independently (but unitarily): u according to H, and v according to I.