3 ms·
I reckon an equal area projection for a full hemisphere would lead to some unacceptable degree of distortion. It's hard to say exactly but it shouldn't be too d
by contravariant 8y ago
I reckon an equal area projection for a full hemisphere would lead to some unacceptable degree of distortion. It's hard to say exactly but it shouldn't be too difficult to see that a cube is closer to a sphere than two squares stuck together.
Edit: it may also be easier to figure out which squares are adjacent when using a grid based on a cube.
- gct 8y agoYeah I guess it depends on what you're trying to optimize (they use web mercator because roads didn't meet at right angles up north for example). But if you're mostly interested in indexing physical areas with polygon approximations, it seems like having each cell be the same area would be the ideal, but idk.