7 ms·
For x sufficiently small, sin(x) looks like x (x in radians). That's because if you write the Taylor's series expansion of sin(x) and ignore high order terms,
by drallison 16y ago
For x sufficiently small, sin(x) looks like x (x in radians). That's because if you write the Taylor's series expansion of sin(x) and ignore high order terms, you get x. The property you are looking for is continuity.