I would say it doesn't really matter much as both are readable. I would prefer either the original if/else or the ternary solution over the last solution as I p

I would say it doesn't really matter much as both are readable. I would prefer either the original if/else or the ternary solution over the last solution as I personally think the intent is not as immediately clear in your "max" form. I would optimize for readability over density, unless there is some reason to write it differently (e.g. performance). just for fun, in kotlin (making use of expressions removes some verbosity): return where(den) { 0 -> 0 else -> num / den } return if (den == 0) { 0 } else { num / den }