3 ms·

Zero goes into zero x times, for any real x. Infinity isn't real, therefore neither is infinity^2 so no.

• westurner 8y ago
  Extrapolate. What value does 1/x approach? What about 2/x? And then, what about ∞/x? What value would we expect that to approach? ∞(±∞)
  • earenndil 8y ago
    It doesn't approach anything, it's unbounded.