2 ms·
That ceases to be a paradox once you distinguish between boundedness versus completeness for a set of infinite steps. There are infinitely many steps on the in
by throwawaymath 8y ago
That ceases to be a paradox once you distinguish between boundedness versus completeness for a set of infinite steps.
There are infinitely many steps on the interval [0,1]. But if you add 1 "step" at any point of the interval greater than 0, you've still "passed" it.