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The default rational type isn't unlimited precision. See my comment at https://www.reddit.com/r/perl/comments/93dabg/perl_6_small_stuff_4_why_perl_isnt_cobol_n
by raiph 8y ago
The default rational type isn't unlimited precision.
See my comment at https://www.reddit.com/r/perl/comments/93dabg/perl_6_small_stuff_4_why_perl_isnt_cobol_nor/e3e21s4 https://www.reddit.com/r/perl/comments/93dabg/perl_6_small_s... for an explanation and demonstration of P6's approach.