4 ms·
Now how about a more complex example? bdP = bdA / pow((1 + bdr / bdm), (bdm - bdt)); bdP = bdA.divide((ONE.add(bdr.divide(bdm))).pow(bdm.subtract(bdt))); Obv
by jacoblambda 8y ago
Now how about a more complex example?
bdP = bdA / pow((1 + bdr / bdm), (bdm - bdt));
bdP = bdA.divide((ONE.add(bdr.divide(bdm))).pow(bdm.subtract(bdt)));
Obviously the first is more transparent than the second and this isn't a particularly complicated equation. Mind you that this can be mostly mitigated by splitting up the equation but that can sometimes make solutions quite opaque comparatively.