> Imaginary numbers are needed to take the square root of a negative No, they are not. That problem is not well defined. A symbol is not a solution. Complex n

> Imaginary numbers are needed to take the square root of a negative No, they are not. That problem is not well defined. A symbol is not a solution. Complex numbers are needed to solve the polynoms of a higher degree. Eg. x^4+x^2=-1 can be simplified to y^2+y=-1 with y=x^2 which wouldn't have a solu