2 ms·
> Is that really a fair characterization? Kind of, but not quite; the problem with a 2-time pad is key cancellation: c1 ^ c2 = (p1 ^ k) ^ (p2 ^ k) = p1 ^ p2. T
by a1369209993 8y ago
> Is that really a fair characterization?
Kind of, but not quite; the problem with a 2-time pad is key cancellation: c1 ^ c2 = (p1 ^ k) ^ (p2 ^ k) = p1 ^ p2. The xor[0] of two plaintexts is only challenging to cryptanalyze if high-entropy sensitive information happens to line up in just the right way.
0: Technically sum mod 26 or so - xor is sum mod 2 - but the same tricks apply.